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Sudoku round 3 - Divisor Sudoku 12

published by zabijaka82 on Sat, 03/12/2016 - 11:56
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General discussion

Hi everyone,
could You give me any advice/clue for this type of sudoku. I had put 3,6 and 9 at center part of grid, but now i have problem with others digits.
I understand rules but can't do more moves (others sudoku's I did).

I wouldn't shoot so maybe you give me a "green ligth" to go forward

Submitted by Fred76 on Mon, 03/14/2016 - 13:10.

Hi,

To continue with the resolution, you have to understand how the divisor 3 works with 2-digits numbers. Either the 2-digits number is composed by 2 digits from the set [369], either it's composed by one digit from the set [147] and another digit from the set [258]. Then in rows and columns 1 and 9, where you have 4 numbers with divisor 3, the leftover digit must be one of the set [369]. Then in rows and columns 1 and 9, you have triples (3 cells with only 3 candidates) 369. Then you can mark the even cells from divisor 2. Combining all the informations should help you to finish solving this.

I made a short video of the solving of this sudoku, you can see it there:
https://www.youtube.com/watch?v=I0XFWR8qmyQ

(BTW: very nice sudoku !)

Fred

Submitted by zabijaka82 on Tue, 03/15/2016 - 07:02.

Amazing:-)
now i understand two thinks .

1. How can We do it so fast(6.30minutes!!!!)

and

2. The solution it's possible.

But first off all thank You so much for help. I stopped film after 1minute. I did the even cells as You said above. But I need more time to understand, why are You so self-confident one's words "Then in rows and columns 1 and 9, you have triples (3 cells with only 3 candidates) 369." :-)

Best wishes
Zabi82